Re: [tlaplus] Assign incremental IDs to sets of functions

Now you can define your operator as follows:

tableInit ==

[person \in group |->

[ status |-> "Active",

divisions |-> LET divs == SetToSeq(getDivisions(person))

IN { [id |-> i, assignedDivision |-> divs[i]] :

i \in 1 .. Len(divs) } ]]

Instead of representing `divs' as a set of records with id fields, you could represent it as a sequence where the id is implicit in the position of the element in the sequence. However, I wonder if you are at the right level of abstraction for your specification: all the information that you need is contained in the set `group' and the operator `getDivisions'. Is it important to construct an explicit data structure that materializes that information, in particular since you don't care about the order of IDs?

Stephan

On 11 Nov 2020, at 06:53, tlalearner <squally3.1@xxxxxxxxx> wrote:

I have a very simple initialization for a function as follows:

sampleTableINIT ==
sampleTable = [person \in group |->
[
status |-> "Active",
divisions |-> {[assignedDivision |-> division] : division \in getDivisions(person)}
]]

Here is a sample result from the definition:

[Sam :> [status |-> "Active", divisions |-> { [assignedDivision |-> "Sales"]]
[Mary :> [status |-> "Active", divisions |-> { [assignedDivision |-> "Sales"], [assignedDivision |-> "CS" }]

What I'd like to accomplish is simple: Per person entry, I'd like to assign an ID per division. The result below is what I want:

[Sam :> [status |-> "Active", divisions |-> { [id |-> 1, assignedDivision |-> "Sales"]]
[Mary :> [status |-> "Active", divisions |-> { [id |-> 1, assignedDivision |-> "Sales"], [id |-> 2, assignedDivision |-> "CS" }]

Order on ID assignment does not matter. Is there an easy way to do this rather than mutating the function in a future state?

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