It seems that it treats [a |-> b] as a record
>> [a |-> b] is a record. Valid access operation on this would be [a |-> b].a (or [a |-> b]["a"]). Note that a is a string here. So [a |-> b]["a"] = [a |-> b].a = b is true.
But my purpose is to add a tuple of (a, b) to the function f
>> This can be done like this: Add(a, b) == f' = [f EXCEPT![a] = b]. This is equivalent to f' = [x \in DOMAIN f |-> IF x = a THEN b ELSE f[x]].
I strongly recommend reading Lamport's Specifying Systems. Chapter 16 covers Functions and Records. Also, if I am not wrong, your TypeOK is incorrect. SUBSET [A -> B] is set of sets of functions in [A -> B]. So, f \subseteq [A -> B] means f is a set of some functions in [A -> B].
Regarding the initial question of defining a partial function, I'm not sure if syntax is available in TLA+ for partial functions, but I could be wrong. The way I specify this is:
CONSTANT None
ASSUME NoneNotInB == None \notin B
Init == f = [x \in A |-> None]
Add(a, b) == f' = [f EXCEPT![a] = b]
TypeOK == f \in [A -> B \cup {None}]
Or if you do not like None and want to express f as a set then,
Init == f = {}
Add(a, b) == f' = f \cup {[a |-> a, b |-> b]}
TypeOK == f \subseteq [a : A, b : B]
Hope this helps,
Saksham
On Tuesday, January 16, 2018 at 2:43:45 PM UTC-5, mlj...@xxxxxxxxx wrote:Hi guys,I've met some problems of function definitions. For instance, in math, I've got two sets A and B; and I'd like to define a partial function f as A -|-> B. Also, I want to define an operation that adding an element to the set, like f' = f \cup {(a, b)}, where a \in A and b \in B.
So in TLA+, I tried to write the spec like:
CONSTANT A, B
VARIABLES f
TypeOK == f \subseteq [A -> B]
Init == f = {}
Add(a, b) == f' = f \cup {[a |-> b]}
Next == \E a \in A, b \in B : Add(a, b)
However, I got errors when running model checking in TLC. It seems that it treats [a |-> b] as a record. But my purpose is to add a tuple of (a, b) to the function f, where f should be a set of tuples as it defined in math, like {(a1, b1), (a2, b2)}.
So how can I write it in TLA+?
Best Regards,
Changjian Zhang