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Re: [tlaplus] How to get a set like this in TLA+?

Yes,that's exactly what I want,thank you.

Hello,

using TLC for evaluating the constant _expression_ [1]

{{xx, yy, zz} : xx \in 1 .. 2, yy \in 3 .. 4, zz \in 5 .. 6}

produces

{ {1, 3, 5},
{1, 3, 6},
{1, 4, 5},
{1, 4, 6},
{2, 3, 5},
{2, 3, 6},
{2, 4, 5},
{2, 4, 6} }

Is this what you had in mind?

Stephan

[1] Note that TLC will complain if the base sets are not homogeneous, for example if you mix integers and strings.

On 22 Dec 2022, at 14:18, Delta Striker <unicorn8...@xxxxxxxxx> wrote:

Hello I'm a newbie in TLA+.

I knew that Cartesian product is something like this:
S × T × U = {<<a, b, c>> : a ∈ S, b ∈ T,c ∈ U }.

And I wonder how can I get a set like this:
{{a, b, c} : a ∈ S, b ∈ T,c ∈ U }.

Thank you.

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