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*From*: Rodrick Chapman <rodrick@xxxxxxxxxxxx>*Date*: Fri, 2 Oct 2020 16:42:21 -0700 (PDT)*References*: <3db0a094-02e8-484b-9aae-eb2930f4e269n@googlegroups.com>

It's just syntax. It happens to be syntax that's based on century-old mathematical notation, but at the end of the day, it's still just syntax.

The trouble you’re having is caused by your assumption that Q is defined on the left side of the colon ("\E Q \in Quorum"), and then used on the right side.

But, in fact, Q is actually defined on the right side of the colon and then used on the left. In other words, we define Q and then ask “is there any element in the set Quorum that meets the definition of Q?”

On Friday, October 2, 2020 at 12:44:13 PM UTC-5 franke...@xxxxxxxxx wrote:

Hi,I'm trying to understand this part of the paxos specification. I'm not trying to understand how paxos works, I get that, I'm just trying to understand how to read and understand this part of the specification.01 /\ \E Q \in Quorum :02 LET Q1b == {m \in msgs : /\ m.type = "1b"03 /\ m.acc \in Q04 /\ m.bal = b}05 Q1bv == {m \in Q1b : m.mbal \geq 0}06 IN /\ \A a \in Q : \E m \in Q1b : m.acc = a07 /\ \/ Q1bv = {}08 \/ \E m \in Q1bv :09 /\ m.mval = v10 /\ \A mm \in Q1bv : m.mbal \geq mm.mbalOn line 01 you define that Q is in set of Quorum and then lines 02-10 define what Q will be. My confusion is on Line 03 Q is referenced. How can you reference something that hasn't been assigned a value yet.I may very well be suffering from "... brain washing done by years of C programming".Any help that I could get in understanding this would be greatly appreciated. Also, is there a place on the web were I can better familiarize my self with such concepts.Thanks,-Frank

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**Follow-Ups**:**Re: [tlaplus] Re: [Newbie Question] Engineer trying to get maths meaning***From:*Stephan Merz

**References**:**[tlaplus] [Newbie Question] Engineer trying to get maths meaning***From:*Frank Eaves

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