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Re: [tlaplus] Constant conversion into Set



But this will share the length of the string but not the actual values of the string. 

I need the values as mentioned. 

On Sun, Jun 23, 2019, 6:44 PM Stephan Merz <stephan.merz@xxxxxxxxx> wrote:
Strings are sequences of characters, and it looks like you want to compute the set of characters contained in a string. For an arbitrary sequence (hence in particular for a string), its range can be defined as

Range(seq) == { seq[i] : i \in 1 .. Len(seq) }

Stephan

On 23 Jun 2019, at 15:32, MK Bug <android.ruba@xxxxxxxxx> wrote:

I am new in tla+, I want to convert 

Z='somevalue'

Into

S= {'s','o','m','e','v','a','l','u','e'}

This is the only conversion I want or can anyone suggest how to split values in tla+

Thanks

On Sun, Jun 23, 2019, 6:17 PM Stephan Merz <stephan.merz@xxxxxxxxx> wrote:
Hello,

I find it hard to understand your question: since TLA+ is based on Zermelo-Fraenkel set theory, formally all values are sets (although it is easier to think of objects such as numbers, strings or functions as being separate entities since we don't know which elements they contain when considered as sets). There is no need to "convert" constants into sets.

For the rest, the syntax that you use is not that of TLA+, which doesn't help me understand your problem.

May I suggest that you study the introductory material about TLA+ [1,2] and come back when you have precise questions?

Thank you,
Stephan



On 22 Jun 2019, at 20:21, MK Bug <android.ruba@xxxxxxxxx> wrote:

Please share how to convert a constant into a set.

For Eaxample:

Constant A    ----Contains value 'ABCnma12'

Set B {'A','B','C','n','m','a','1','2'}

Thanks in advance.

Regards,
Malaika

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