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Re: [tlaplus] Re: Understand symmetric set



According to your declaration of symmetry, <<b,a>> is considered equivalent to <<a,b>>, and <<b,b>> is equivalent to <<a,a>>.

Stephan

On 25 Mar 2019, at 07:09, Shiyao MA <i@xxxxxxxxx> wrote:

To be specific. For the example,

CONSTANT Foos
\* ...
variables x \in Foos, y \in Foos;
begin
    print <<x, y>>;
end algorithm;

where Foos = {a, b} and declared symmetric.

Then only <<a, b>>, and <<a, a>> will be outputted.  but not <<b, b>>.

Why is that?

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