According to your declaration of symmetry, <<b,a>> is considered equivalent to <<a,b>>, and <<b,b>> is equivalent to <<a,a>>.
Stephan On 25 Mar 2019, at 07:09, Shiyao MA < i@xxxxxxxxx> wrote:
To be specific. For the example, CONSTANT Foos \* ... variables x \in Foos, y \in Foos; begin print <<x, y>>; end algorithm;
where Foos = {a, b} and declared symmetric.
Then only <<a, b>>, and <<a, a>> will be outputted. but not <<b, b>>.
Why is that?
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