[tlaplus] another simple theorem

[jack malkovick <sillymouse333@xxxxxxxxx>]

How could I help TLAPS to prove this simple theorem?

THEOREM TT ==
    ASSUME
        NEW P(_), NEW Q(_)
    PROVE
        \A x : (P(x) # Q(x)) => (P(x) = ~Q(x)) 
    PROOF
        OBVIOUS

PS. it can prove with no problem the reverse implication

       \A x : (P(x) = ~Q(x)) => (P(x) # Q(x))

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