In the video, around 8:58, the Next action is defined as
A \/ B
meaning it's an A step or a B step ... but isn't the case where
the step is BOTH an A step and a B step allowed by this
_expression_?
Later, A and B are defined so that A explicitly says BVar' = BVar
is unchanged and B says AVar' = AVar is unchenced. So if both
A and B occur in a Next, it amounts to a stuttering step.
I just want to make sure I understand
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