Unfortunately, TLAPS does not yet handle first-order temporal logic and cannot prove this obligation at this point.--StephanOn 17 Oct 2019, at 16:39, Saswata Paul <paulsaswata1@xxxxxxxxx> wrote:HI,I have been learning temporal logic with TLAPS.I noticed that in TLAPS, if we have \A x \in SomeSet : <> <<A(x)>>_vars => <> <<B(x)>>_vars and <> <<A(x)>>_vars in the assumption base and try to prove <> <<B(x)>>_vars from it, the prover fails.However, we can prove B(x) from \A x \in SomeSet : A(x) => B(x) and A(x).Since I have no prior experience with temporal logic, I was wondering whether this is a limitation of temporal logic itself (if it is, then why?) or a limitation of TLAPS.Any clarification will be appreciated.Thank you--
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