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Re: [tlaplus] Symmetry sets



An update to my own message. Turns out that I missed the syntax difference between

	item \in {x \in Set: P(x)}

vs

	item = {x \in Set: P(x)}

The former, which is what you recommended in the first place, gives me exactly one item at a time. I can get rid of CHOOSE! Thank you.

— 
Philip

> On Feb 14, 2019, at 4:21 PM, Philip White <philip@xxxxxxxxxxxxx> wrote:
> 
> I see… yes, I was expecting TLC to try all selections. Thank you very much for clarifying this newbie mistake.
> 
> What I like about CHOOSE is that it will select exactly one item, or give a model error if it couldn’t find one. With the second (symmetric) syntax you suggest, we get a set, and the set may be empty. To make up for CHOOSE’s functionality, is using a type invariant the answer?
> 
> Philip
> 
> 
>> On Feb 14, 2019, at 12:18 PM, Hillel Wayne <hwayne@xxxxxxxxx> wrote:
>> 
>> Hi Philip,
>> 
>> It sounds like there might be an XY problem here. CHOOSE is consistent: for the same set and predicate, it will choose the same element across all behaviors. If you're expecting TLC to try all selections, this could lead to your spec passing when you think it should fail. This is a common pitfall for beginners, which is why I'm bringing it up now.
>> 
>> If this is an issue in your spec, you can replace
>> 
>> item' = CHOOSE x \in Set: P(x)
>> 
>> with
>> 
>> item' \in {x \in Set: P(x)}
>> 
>> which retains symmetry.
>> 
>> H
> 
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