Hi,
Sets are fine and I have modified the spec accordingly, also I removed the LET \intersect as you suggested and it works. About the CHOOSE, in theory it shouldn't matter that it is deterministic, the important requirement is even distribution. But, I need to consider that point more deeply.
Regarding your much scaled down version, it is almost there but not quite.
BalancedAllocations == { reg \in [N -> R] : IsBalanced(reg) }
fails with
Attempted to apply the operator overridden by the Java method
public static tlc2.value.IntValue tlc2.module.FiniteSets.Cardinality(tlc2.value.Value),
but it produced the following error:
Attemtped to compute cardinality of the value
"r1"
If I modify it to be:
BalancedAllocations == { reg \in [N -> SUBSET R] : IsBalanced(reg) }
Then it doesn't fail but happily makes no assignments.
If I modify it to be:
BalancedAllocations == { reg \in [N -> {R}] : IsBalanced(reg) }
then it assigns all resources to all nodes.
So it needs a tweak to make sure it assigns all resources, but without assigning the same resource twice which is an invariant of the algorithm.
I will have a crack at that tomorrow.
Thanks
Jack
On Wednesday, January 16, 2019 at 5:35:42 PM UTC+1, Jack Vanlightly wrote:
Hi,
I have a set of nodes N, a set of resources R and a function "register" that maps N to R. The algorithm is a resource allocation algorithm that must assign the resources of R evenly across the nodes N.
So if N is { "n1", "n2", "n3"} and R is {"r1", "r2", "r3", "r4" } then once allocation has taken place a valid value for register would be:
[n1 |-> <<"r4", "r1">>, n2 |-> <<"r2">>, n3 |-> <<"r3">>]
I want to set the values of register in a single step and I have managed it, though the formula seems overly complex and I wonder if there is a simpler way of doing that would help me also gain more insight into TLA+.
I have isolated the allocation logic into a toy spec as follows:
EXTENDS Integers, FiniteSets, Sequences, TLC
CONSTANT R, N
VARIABLE register
Init ==
register = [n \in N |-> << >>]
HasMinResources(counts, nd) ==
\A x \in N : counts[nd] <= counts[x]
Allocate ==
LET newRegister == [n \in N |-> << >>]
counts == [n \in N |-> 0]
al[pendingRes \in SUBSET R, assignCount \in [N -> Nat]] ==
LET n == CHOOSE nd \in N : HasMinResources(assignCount, nd)
r == LET int == R \intersect pendingRes
IN CHOOSE x \in int : TRUE
IN
IF Cardinality(pendingRes) = 0 THEN newRegister
ELSE
LET remaining == pendingRes \ { r }
newAssignCount == [assignCount EXCEPT ![n] = @ + 1]
IN [al[remaining, newAssignCount] EXCEPT ![n] = Append(@, r)]
IN al[R, counts]
Rebalance ==
/\ register' = Allocate
/\ PrintT(register')
(* ignore the spec, I just wanted to run the Rebalance action once *)
Spec == Init /\ [][Rebalance]_register
Notes:
- I made Allocate recursive as that is the only way I could figure out making all the changes to register in a single step.
- I did the intersect so that I could use CHOOSE. Else it complained that is was an unbounded CHOOSE so I figured if I did an intersect with R then it would be interpretted as bounded.
Any insights or suggestions would be great.
Thanks
Jack