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*From*: Jam <wawrzynchonewicz@xxxxxxxxx>*Date*: Wed, 24 Apr 2019 05:25:20 -0700 (PDT)*References*: <b9fae7aa-2b2f-4baa-b02d-3dc0bc8b907e@googlegroups.com>

Well, I have figured it out. With the help of https://learntla.com/tla/ , i learned that tuples are functions and found a useful operator:

which I then use as follows to get what I need:

On Wednesday, April 24, 2019 at 12:38:32 PM UTC+2, Jam wrote:

-- `Range(T) == { T[x] : x \in DOMAIN T }`

Seq2(S, n) == UNION {[1..m -> S] : m \in 1..n}

which I then use as follows to get what I need:

`SetToTuple(set) ==`

CHOOSE x \in Seq2(set, Cardinality(set)) : Range(x) = set

It's no joke that TLA+ has a steep learning curve!

On Wednesday, April 24, 2019 at 12:38:32 PM UTC+2, Jam wrote:

Hello. I'm struggling with a seemingly simple conversion of a set of N elements into a tuple with those same elements. One way I think this could be done (I haven't tried this, because i don't want this) is:

VARIABLES i, tuple, set, temp

Convert ==

/\ i < Cardinality(set)

/\ temp = CHOOSE x \in set : TRUE \* I don't even know how to pull them in order

/\ set' = set \ temp

/\ tuple' = Append(tuple, temp)

/\ i' = i + 1I don't like this solution because it requires multiple steps, destroys the original, and quite frankly, is ridiculous.Is there a way of doing it in just one step? And preferably without variables (if i remember correctly there are variables for preserving state between steps, and values for computing state within a step)? The reason I need this is because i have a queue (which internally is a tuple), and i need to enqueue 2 things in one step. I figured maybe I can do this by

queue' = queue \o multiple_elementsbut for this i need multiple_elements to be a tuple, and currently its a set.

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