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# Simpler method of making multiple changes to a function in a single step

Hi,

I have a set of nodes N, a set of resources R and a function "register" that maps N to R. The algorithm is a resource allocation algorithm that must assign the resources of R evenly across the nodes N.

So if N is { "n1", "n2", "n3"} and R is {"r1", "r2", "r3", "r4" } then once allocation has taken place a valid value for register would be:
[n1 |-> <<"r4", "r1">>, n2 |-> <<"r2">>, n3 |-> <<"r3">>]

I want to set the values of register in a single step and I have managed it, though the formula seems overly complex and I wonder if there is a simpler way of doing that would help me also gain more insight into TLA+.

I have isolated the allocation logic into a toy spec as follows:

EXTENDS Integers, FiniteSets, Sequences, TLC
CONSTANT R, N
VARIABLE register

Init ==
register = [n \in N |-> << >>]

HasMinResources(counts, nd) ==
\A x \in N : counts[nd] <= counts[x]

Allocate ==
LET newRegister == [n \in N |-> << >>]
counts == [n \in N |-> 0]
al[pendingRes \in SUBSET R, assignCount \in [N -> Nat]] ==
LET n == CHOOSE nd \in N : HasMinResources(assignCount, nd)
r == LET int == R \intersect pendingRes
IN CHOOSE x \in int : TRUE
IN
IF Cardinality(pendingRes) = 0 THEN newRegister
ELSE
LET remaining == pendingRes \ { r }
newAssignCount == [assignCount EXCEPT ![n] = @ + 1]
IN [al[remaining, newAssignCount] EXCEPT ![n] = Append(@, r)]
IN al[R, counts]

Rebalance ==
/\ register' = Allocate
/\ PrintT(register')

(* ignore the spec, I just wanted to run the Rebalance action once *)
Spec == Init /\ [][Rebalance]_register

Notes:
- I made Allocate recursive as that is the only way I could figure out making all the changes to register in a single step.
- I did the intersect so that I could use CHOOSE. Else it complained that is was an unbounded CHOOSE so I figured if I did an intersect with R then it would be interpretted as bounded.

Any insights or suggestions would be great.

Thanks
Jack